3.448 \(\int (f x)^m (d+e x^r)^3 (a+b \log (c x^n))^p \, dx\)

Optimal. Leaf size=480 \[ \frac {d^3 (f x)^{m+1} e^{-\frac {a (m+1)}{b n}} \left (c x^n\right )^{-\frac {m+1}{n}} \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(m+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \Gamma \left (p+1,-\frac {(m+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{f (m+1)}+\frac {3 d^2 e x^{r+1} (f x)^m e^{-\frac {a (m+r+1)}{b n}} \left (c x^n\right )^{-\frac {m+r+1}{n}} \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(m+r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \Gamma \left (p+1,-\frac {(m+r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{m+r+1}+\frac {3 d e^2 x^{2 r+1} (f x)^m e^{-\frac {a (m+2 r+1)}{b n}} \left (c x^n\right )^{-\frac {m+2 r+1}{n}} \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(m+2 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \Gamma \left (p+1,-\frac {(m+2 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{m+2 r+1}+\frac {e^3 x^{3 r+1} (f x)^m e^{-\frac {a (m+3 r+1)}{b n}} \left (c x^n\right )^{-\frac {m+3 r+1}{n}} \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(m+3 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \Gamma \left (p+1,-\frac {(m+3 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{m+3 r+1} \]

[Out]

d^3*(f*x)^(1+m)*GAMMA(1+p,-(1+m)*(a+b*ln(c*x^n))/b/n)*(a+b*ln(c*x^n))^p/exp(a*(1+m)/b/n)/f/(1+m)/((c*x^n)^((1+
m)/n))/((-(1+m)*(a+b*ln(c*x^n))/b/n)^p)+3*d^2*e*x^(1+r)*(f*x)^m*GAMMA(1+p,-(1+m+r)*(a+b*ln(c*x^n))/b/n)*(a+b*l
n(c*x^n))^p/exp(a*(1+m+r)/b/n)/(1+m+r)/((c*x^n)^((1+m+r)/n))/((-(1+m+r)*(a+b*ln(c*x^n))/b/n)^p)+3*d*e^2*x^(1+2
*r)*(f*x)^m*GAMMA(1+p,-(1+m+2*r)*(a+b*ln(c*x^n))/b/n)*(a+b*ln(c*x^n))^p/exp(a*(1+m+2*r)/b/n)/(1+m+2*r)/((c*x^n
)^((1+m+2*r)/n))/((-(1+m+2*r)*(a+b*ln(c*x^n))/b/n)^p)+e^3*x^(1+3*r)*(f*x)^m*GAMMA(1+p,-(1+m+3*r)*(a+b*ln(c*x^n
))/b/n)*(a+b*ln(c*x^n))^p/exp(a*(1+m+3*r)/b/n)/(1+m+3*r)/((c*x^n)^((1+m+3*r)/n))/((-(1+m+3*r)*(a+b*ln(c*x^n))/
b/n)^p)

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Rubi [A]  time = 0.66, antiderivative size = 480, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 4, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.148, Rules used = {2353, 2310, 2181, 20} \[ \frac {3 d^2 e x^{r+1} (f x)^m e^{-\frac {a (m+r+1)}{b n}} \left (c x^n\right )^{-\frac {m+r+1}{n}} \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(m+r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \text {Gamma}\left (p+1,-\frac {(m+r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{m+r+1}+\frac {d^3 (f x)^{m+1} e^{-\frac {a (m+1)}{b n}} \left (c x^n\right )^{-\frac {m+1}{n}} \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(m+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \text {Gamma}\left (p+1,-\frac {(m+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{f (m+1)}+\frac {3 d e^2 x^{2 r+1} (f x)^m e^{-\frac {a (m+2 r+1)}{b n}} \left (c x^n\right )^{-\frac {m+2 r+1}{n}} \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(m+2 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \text {Gamma}\left (p+1,-\frac {(m+2 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{m+2 r+1}+\frac {e^3 x^{3 r+1} (f x)^m e^{-\frac {a (m+3 r+1)}{b n}} \left (c x^n\right )^{-\frac {m+3 r+1}{n}} \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(m+3 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \text {Gamma}\left (p+1,-\frac {(m+3 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{m+3 r+1} \]

Antiderivative was successfully verified.

[In]

Int[(f*x)^m*(d + e*x^r)^3*(a + b*Log[c*x^n])^p,x]

[Out]

(d^3*(f*x)^(1 + m)*Gamma[1 + p, -(((1 + m)*(a + b*Log[c*x^n]))/(b*n))]*(a + b*Log[c*x^n])^p)/(E^((a*(1 + m))/(
b*n))*f*(1 + m)*(c*x^n)^((1 + m)/n)*(-(((1 + m)*(a + b*Log[c*x^n]))/(b*n)))^p) + (3*d^2*e*x^(1 + r)*(f*x)^m*Ga
mma[1 + p, -(((1 + m + r)*(a + b*Log[c*x^n]))/(b*n))]*(a + b*Log[c*x^n])^p)/(E^((a*(1 + m + r))/(b*n))*(1 + m
+ r)*(c*x^n)^((1 + m + r)/n)*(-(((1 + m + r)*(a + b*Log[c*x^n]))/(b*n)))^p) + (3*d*e^2*x^(1 + 2*r)*(f*x)^m*Gam
ma[1 + p, -(((1 + m + 2*r)*(a + b*Log[c*x^n]))/(b*n))]*(a + b*Log[c*x^n])^p)/(E^((a*(1 + m + 2*r))/(b*n))*(1 +
 m + 2*r)*(c*x^n)^((1 + m + 2*r)/n)*(-(((1 + m + 2*r)*(a + b*Log[c*x^n]))/(b*n)))^p) + (e^3*x^(1 + 3*r)*(f*x)^
m*Gamma[1 + p, -(((1 + m + 3*r)*(a + b*Log[c*x^n]))/(b*n))]*(a + b*Log[c*x^n])^p)/(E^((a*(1 + m + 3*r))/(b*n))
*(1 + m + 3*r)*(c*x^n)^((1 + m + 3*r)/n)*(-(((1 + m + 3*r)*(a + b*Log[c*x^n]))/(b*n)))^p)

Rule 20

Int[(u_.)*((a_.)*(v_))^(m_)*((b_.)*(v_))^(n_), x_Symbol] :> Dist[(b^IntPart[n]*(b*v)^FracPart[n])/(a^IntPart[n
]*(a*v)^FracPart[n]), Int[u*(a*v)^(m + n), x], x] /; FreeQ[{a, b, m, n}, x] &&  !IntegerQ[m] &&  !IntegerQ[n]
&&  !IntegerQ[m + n]

Rule 2181

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> -Simp[(F^(g*(e - (c*f)/d))*(c +
d*x)^FracPart[m]*Gamma[m + 1, (-((f*g*Log[F])/d))*(c + d*x)])/(d*(-((f*g*Log[F])/d))^(IntPart[m] + 1)*(-((f*g*
Log[F]*(c + d*x))/d))^FracPart[m]), x] /; FreeQ[{F, c, d, e, f, g, m}, x] &&  !IntegerQ[m]

Rule 2310

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_)*((d_.)*(x_))^(m_.), x_Symbol] :> Dist[(d*x)^(m + 1)/(d*n*(c*x^n
)^((m + 1)/n)), Subst[Int[E^(((m + 1)*x)/n)*(a + b*x)^p, x], x, Log[c*x^n]], x] /; FreeQ[{a, b, c, d, m, n, p}
, x]

Rule 2353

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^(r_.))^(q_.), x_Symbol]
:> With[{u = ExpandIntegrand[(a + b*Log[c*x^n])^p, (f*x)^m*(d + e*x^r)^q, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[
{a, b, c, d, e, f, m, n, p, q, r}, x] && IntegerQ[q] && (GtQ[q, 0] || (IGtQ[p, 0] && IntegerQ[m] && IntegerQ[r
]))

Rubi steps

\begin {align*} \int (f x)^m \left (d+e x^r\right )^3 \left (a+b \log \left (c x^n\right )\right )^p \, dx &=\int \left (d^3 (f x)^m \left (a+b \log \left (c x^n\right )\right )^p+3 d^2 e x^r (f x)^m \left (a+b \log \left (c x^n\right )\right )^p+3 d e^2 x^{2 r} (f x)^m \left (a+b \log \left (c x^n\right )\right )^p+e^3 x^{3 r} (f x)^m \left (a+b \log \left (c x^n\right )\right )^p\right ) \, dx\\ &=d^3 \int (f x)^m \left (a+b \log \left (c x^n\right )\right )^p \, dx+\left (3 d^2 e\right ) \int x^r (f x)^m \left (a+b \log \left (c x^n\right )\right )^p \, dx+\left (3 d e^2\right ) \int x^{2 r} (f x)^m \left (a+b \log \left (c x^n\right )\right )^p \, dx+e^3 \int x^{3 r} (f x)^m \left (a+b \log \left (c x^n\right )\right )^p \, dx\\ &=\left (3 d^2 e x^{-m} (f x)^m\right ) \int x^{m+r} \left (a+b \log \left (c x^n\right )\right )^p \, dx+\left (3 d e^2 x^{-m} (f x)^m\right ) \int x^{m+2 r} \left (a+b \log \left (c x^n\right )\right )^p \, dx+\left (e^3 x^{-m} (f x)^m\right ) \int x^{m+3 r} \left (a+b \log \left (c x^n\right )\right )^p \, dx+\frac {\left (d^3 (f x)^{1+m} \left (c x^n\right )^{-\frac {1+m}{n}}\right ) \operatorname {Subst}\left (\int e^{\frac {(1+m) x}{n}} (a+b x)^p \, dx,x,\log \left (c x^n\right )\right )}{f n}\\ &=\frac {d^3 e^{-\frac {a (1+m)}{b n}} (f x)^{1+m} \left (c x^n\right )^{-\frac {1+m}{n}} \Gamma \left (1+p,-\frac {(1+m) \left (a+b \log \left (c x^n\right )\right )}{b n}\right ) \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(1+m) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p}}{f (1+m)}+\frac {\left (3 d^2 e x^{1+r} (f x)^m \left (c x^n\right )^{-\frac {1+m+r}{n}}\right ) \operatorname {Subst}\left (\int e^{\frac {(1+m+r) x}{n}} (a+b x)^p \, dx,x,\log \left (c x^n\right )\right )}{n}+\frac {\left (3 d e^2 x^{1+2 r} (f x)^m \left (c x^n\right )^{-\frac {1+m+2 r}{n}}\right ) \operatorname {Subst}\left (\int e^{\frac {(1+m+2 r) x}{n}} (a+b x)^p \, dx,x,\log \left (c x^n\right )\right )}{n}+\frac {\left (e^3 x^{1+3 r} (f x)^m \left (c x^n\right )^{-\frac {1+m+3 r}{n}}\right ) \operatorname {Subst}\left (\int e^{\frac {(1+m+3 r) x}{n}} (a+b x)^p \, dx,x,\log \left (c x^n\right )\right )}{n}\\ &=\frac {d^3 e^{-\frac {a (1+m)}{b n}} (f x)^{1+m} \left (c x^n\right )^{-\frac {1+m}{n}} \Gamma \left (1+p,-\frac {(1+m) \left (a+b \log \left (c x^n\right )\right )}{b n}\right ) \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(1+m) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p}}{f (1+m)}+\frac {3 d^2 e e^{-\frac {a (1+m+r)}{b n}} x^{1+r} (f x)^m \left (c x^n\right )^{-\frac {1+m+r}{n}} \Gamma \left (1+p,-\frac {(1+m+r) \left (a+b \log \left (c x^n\right )\right )}{b n}\right ) \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(1+m+r) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p}}{1+m+r}+\frac {3 d e^2 e^{-\frac {a (1+m+2 r)}{b n}} x^{1+2 r} (f x)^m \left (c x^n\right )^{-\frac {1+m+2 r}{n}} \Gamma \left (1+p,-\frac {(1+m+2 r) \left (a+b \log \left (c x^n\right )\right )}{b n}\right ) \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(1+m+2 r) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p}}{1+m+2 r}+\frac {e^3 e^{-\frac {a (1+m+3 r)}{b n}} x^{1+3 r} (f x)^m \left (c x^n\right )^{-\frac {1+m+3 r}{n}} \Gamma \left (1+p,-\frac {(1+m+3 r) \left (a+b \log \left (c x^n\right )\right )}{b n}\right ) \left (a+b \log \left (c x^n\right )\right )^p \left (-\frac {(1+m+3 r) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p}}{1+m+3 r}\\ \end {align*}

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Mathematica [A]  time = 1.90, size = 408, normalized size = 0.85 \[ x^{-m} (f x)^m \left (a+b \log \left (c x^n\right )\right )^p \left (\frac {d^3 \exp \left (-\frac {(m+1) \left (a+b \log \left (c x^n\right )-b n \log (x)\right )}{b n}\right ) \left (-\frac {(m+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \Gamma \left (p+1,-\frac {(m+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{m+1}+e \left (\frac {3 d^2 \exp \left (-\frac {(m+r+1) \left (a+b \log \left (c x^n\right )-b n \log (x)\right )}{b n}\right ) \left (-\frac {(m+r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \Gamma \left (p+1,-\frac {(m+r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{m+r+1}+e \left (\frac {3 d \exp \left (-\frac {(m+2 r+1) \left (a+b \log \left (c x^n\right )-b n \log (x)\right )}{b n}\right ) \left (-\frac {(m+2 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \Gamma \left (p+1,-\frac {(m+2 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{m+2 r+1}+\frac {e \exp \left (-\frac {(m+3 r+1) \left (a+b \log \left (c x^n\right )-b n \log (x)\right )}{b n}\right ) \left (-\frac {(m+3 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )^{-p} \Gamma \left (p+1,-\frac {(m+3 r+1) \left (a+b \log \left (c x^n\right )\right )}{b n}\right )}{m+3 r+1}\right )\right )\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[(f*x)^m*(d + e*x^r)^3*(a + b*Log[c*x^n])^p,x]

[Out]

((f*x)^m*(a + b*Log[c*x^n])^p*((d^3*Gamma[1 + p, -(((1 + m)*(a + b*Log[c*x^n]))/(b*n))])/(E^(((1 + m)*(a - b*n
*Log[x] + b*Log[c*x^n]))/(b*n))*(1 + m)*(-(((1 + m)*(a + b*Log[c*x^n]))/(b*n)))^p) + e*((3*d^2*Gamma[1 + p, -(
((1 + m + r)*(a + b*Log[c*x^n]))/(b*n))])/(E^(((1 + m + r)*(a - b*n*Log[x] + b*Log[c*x^n]))/(b*n))*(1 + m + r)
*(-(((1 + m + r)*(a + b*Log[c*x^n]))/(b*n)))^p) + e*((3*d*Gamma[1 + p, -(((1 + m + 2*r)*(a + b*Log[c*x^n]))/(b
*n))])/(E^(((1 + m + 2*r)*(a - b*n*Log[x] + b*Log[c*x^n]))/(b*n))*(1 + m + 2*r)*(-(((1 + m + 2*r)*(a + b*Log[c
*x^n]))/(b*n)))^p) + (e*Gamma[1 + p, -(((1 + m + 3*r)*(a + b*Log[c*x^n]))/(b*n))])/(E^(((1 + m + 3*r)*(a - b*n
*Log[x] + b*Log[c*x^n]))/(b*n))*(1 + m + 3*r)*(-(((1 + m + 3*r)*(a + b*Log[c*x^n]))/(b*n)))^p)))))/x^m

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fricas [F]  time = 0.66, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (e^{3} x^{3 \, r} + 3 \, d e^{2} x^{2 \, r} + 3 \, d^{2} e x^{r} + d^{3}\right )} \left (f x\right )^{m} {\left (b \log \left (c x^{n}\right ) + a\right )}^{p}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)^m*(d+e*x^r)^3*(a+b*log(c*x^n))^p,x, algorithm="fricas")

[Out]

integral((e^3*x^(3*r) + 3*d*e^2*x^(2*r) + 3*d^2*e*x^r + d^3)*(f*x)^m*(b*log(c*x^n) + a)^p, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (e x^{r} + d\right )}^{3} \left (f x\right )^{m} {\left (b \log \left (c x^{n}\right ) + a\right )}^{p}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)^m*(d+e*x^r)^3*(a+b*log(c*x^n))^p,x, algorithm="giac")

[Out]

integrate((e*x^r + d)^3*(f*x)^m*(b*log(c*x^n) + a)^p, x)

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maple [F]  time = 1.56, size = 0, normalized size = 0.00 \[ \int \left (e \,x^{r}+d \right )^{3} \left (f x \right )^{m} \left (b \ln \left (c \,x^{n}\right )+a \right )^{p}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((f*x)^m*(e*x^r+d)^3*(b*ln(c*x^n)+a)^p,x)

[Out]

int((f*x)^m*(e*x^r+d)^3*(b*ln(c*x^n)+a)^p,x)

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)^m*(d+e*x^r)^3*(a+b*log(c*x^n))^p,x, algorithm="maxima")

[Out]

Exception raised: RuntimeError >> ECL says: In function CAR, the value of the first argument is  0which is not
 of the expected type LIST

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int {\left (f\,x\right )}^m\,{\left (d+e\,x^r\right )}^3\,{\left (a+b\,\ln \left (c\,x^n\right )\right )}^p \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((f*x)^m*(d + e*x^r)^3*(a + b*log(c*x^n))^p,x)

[Out]

int((f*x)^m*(d + e*x^r)^3*(a + b*log(c*x^n))^p, x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)**m*(d+e*x**r)**3*(a+b*ln(c*x**n))**p,x)

[Out]

Timed out

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